Feedback.
@OOOPS
Which figure can serve as a counterexample to the conjecture below? If one pair of opposite sides of a quadrilateral is parallel, then the quadrilateral is a parallelogram? Rectangle Rhombus Trapezoid Square
Trapezoid better example will be trapezium
thanks, and what about for the first one??
nope for the first one
q= x is NOT a whole number, while the expression is "if x is a whole number" that means ~q , got it?
and p = "x^2=21" so that \(x^2\neq 21\) is ~p combine them you have :
???
~q ~p
~q-->~p
yeah haha sorry I couldnt find the right keys!
ok, as long as you got it, the small mistake is nothing
I've got a quick question for this problem would you just have to find c, the hypotenuse?
Because when I do that it comes out to 68, but it is asking for the new pipeline so I'm not quite sure what to do, I know there is suppose to be subtracting taking place somewhere between these numbers.
nope!!
68 miles is the length of the old one, right?
yes,
the new one is 60+32=92 miles, right?
Correct,
so, the different between them is??
24!
HAha great thanks!!
Pay attention at the question: they ask about "how many EXTRA miles"
got it??
Yeah!
good
How would you solve this, Two angles of a triangle have measures of 55° and 65°. Which of the following could not be a measure of an exterior angle of the triangle? 115o 120o 125o 130o What I did was draw a triangle like this
|dw:1407211149138:dw| its not supposed to be a right triangle... but thats the best I could do in a short amount of time.
I thought it would be 130, because everything below that equals 180 or falls underneath 180, 130 is the only one that goes over 180.
hahahaha... are ....you....so...tired??
yeah, I have slept probably, 5 hours the past three days combined.
|dw:1407211311321:dw|
Join our real-time social learning platform and learn together with your friends!