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OpenStudy (anonymous):
if sin theta -cos theta=0 then sin(pi/2-theta)+cos(pi/2-theta)=?
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OpenStudy (anonymous):
cos theta+sin theta=
OpenStudy (ikram002p):
sin theta -cos theta=0
then
tan theta =1
theta = tan^-1 (1)
so theta = ?
OpenStudy (ikram002p):
or you wanna you sum formula ?
OpenStudy (anonymous):
i need the value of sin theta+cos theta=?
OpenStudy (ikram002p):
well theta = pi/4 :o
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OpenStudy (ikram002p):
@ganeshie8 any other way to solve it ?
OpenStudy (anonymous):
can we do like that sin pi/2-sin theta +cos pi/2-cos theta?
OpenStudy (ikram002p):
well
cos theta =sin theta
and we wanna find cos theta +sin theta =2 cos theta =2 sin theta xD
which i have no idea what is this xD
ganeshie8 (ganeshie8):
we can simply substitute \(\theta = \pi/4\) right ?
OpenStudy (anonymous):
2 sin pi/4=2*1/sqrt(2)=sqrt(2)
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OpenStudy (anonymous):
is it right? @ikram002p
OpenStudy (anonymous):
or sin pi/4+cos pi/4=1/sqrt(2)+1/sqrt(2)=sqrt(2)
OpenStudy (ikram002p):
@ganeshie8 this is what im thinking off :o
but idk if mmm you know mmm identity or hmmm tricky
or mmm hmmm m m m mm
ganeshie8 (ganeshie8):
\(\sin \theta - \cos \theta = 0\)
gives
\(\theta = \frac{\pi}{4} \pm n\pi\)
right ?
ganeshie8 (ganeshie8):
cuz period of \(\tan x\) is \(\pi\)
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OpenStudy (ikram002p):
yeah also dnt forget
|dw:1407227223090:dw|
OpenStudy (anonymous):
3ed?
ganeshie8 (ganeshie8):
|dw:1407227402317:dw|
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