Question

Could somebody please check if I got this right

Integral of cos(x)*e^sin(x)

u=sin(x)
du=cos(x) dx

Integral cos(x)*cos(x)*e^u dx

1/cos(x) integral cos(x)*e^u du

e^sin(x) +c

Answer 1

the answer is ok, the process is a little bit not correct, hihihi

Answer 2

Ok could you please show me how

Answer 3

It probably should of been integral cos(x)*e^u dx

Answer 4

u = sinx --> du = cosx dx,
\[\int cosx e^{sinx}dx = \int e^{sinx}cosx dx\]
replace the substitute in, you have
\[\int e^u du\] that gives you the answer , not as you did

Answer 5

e^u du = e^sin(x) + c

Answer 6

yup

Answer 7

Your process is not correct, re -read, please. YOu must understand what is going on to get the correct answer.