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Evaluate the following expression using the values given: Find -a2 - 3b3 + c2 + 2b3 - c2 if a = 3, b = 2, and c = -3. -67 -17 -31 1 I got 19 what am i doing wrong?
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\[-a ^{2}-3b ^{3}+c ^{2}+2b ^{3}-c ^{2}\]
\[9-3(8)+9+2(8)+9\]
\[9-24+9+16+9\]
\[19\]
Probably -9-24+9+16-9
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the nines become positive because a negative times a negative is positive
But if you square the number first such as a^2 you get 9. The operand comes second thus it is -9
@ganeshie8 @phi @mathstudent55 @zaibali.qasmi @paki ?
so you would put it in parenthesis then square and do the negative?
you were right thanks
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Your welcome...I have been fooled by the same thing
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