Question

Evaluate the following expression using the values given:

Find -a2 - 3b3 + c2 + 2b3 - c2 if a = 3, b = 2, and c = -3.

-67

-17

-31

1

I got 19 what am i doing wrong?

Answer 1

\[-a ^{2}-3b ^{3}+c ^{2}+2b ^{3}-c ^{2}\]

Answer 2

\[9-3(8)+9+2(8)+9\]

Answer 3

\[9-24+9+16+9\]

Answer 4

\[19\]

Answer 5

Probably -9-24+9+16-9

Answer 6

the nines become positive because a negative times a negative is positive

Answer 7

But if you square the number first such as a^2 you get 9. The operand comes second thus it is -9

Answer 8

@ganeshie8 @phi @mathstudent55 @zaibali.qasmi @paki ?

Answer 9

so you would put it in parenthesis then square and do the negative?

Answer 10

you were right thanks

Answer 11

Your welcome...I have been fooled by the same thing