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x% of y is z and (x + 10)% of y is equal to 2z, then y when expressed in terms of z is
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xy/10=z,(x+10)y/100=2z
y=zx/100,yx+10y=200z
zx/100+10zx/100=200z
100z+10y^2-200zy
so we have: \[z = \frac{xy}{100} \rightarrow y = \frac{100z}{x}\] \[2z = \frac{y(x+10)}{100} = \frac{2xy}{100}\] From 2nd equation you can find that x=10 thus \[y = \frac{100z}{10} = 10z\]
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2xy/100 how?
yx+10y/100
i substituted previous value for "z" and multiplied by 2
A one line Mathematica solution is attached.
oh ok
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ahh sorry i realized i didn't make that clear \[2z = 2(\frac{xy}{100}) = \frac{y(x+10)}{100}\]
k no problem
thanks @robtobey
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