Question

HELP FINDING THE MIDPOINT

Answer 1

HELPP

Answer 2

\[\huge \left( \frac{ x _{1}+x _{2} }{ 2 },\frac{ y _{1}+y _{2} }{ 2 }\right)\]

Answer 3

Take the two points

Answer 4

(-3,3.5) (4,-4)???

Answer 5

No

Answer 6

Try reading the graph again, it's important.

Answer 7

(0,-2)(3,2)

Answer 8

huh?

Answer 9

wrong graph !!

Answer 10

xD

Answer 11

(-3,-3)(3,4)

Answer 12

Yeah xD

Answer 13

wait no

Answer 14

(-3,-3)(3,-4)

Answer 15

@iambatman

Answer 16

help with the work

Answer 17

Yeah that's right xD

Answer 18

Just plug it in, you're basically just finding the average.

Answer 19

i can't get it!!

Answer 20

YES YOU CAN!

Answer 21

nooo!!!

Answer 22

\[\huge \left( \frac{ x _{1}+x _{2} }{ 2 },\frac{ y _{1}+y _{2} }{ 2 }\right)\]

Answer 23

i did that

Answer 24

What did you get?

Answer 25

You can compare your answer to the graph =P

Answer 26

So what did you get as the midpoint?

Answer 27

im not doing this right

Answer 28

i think I'm supposed to get square root answers

Answer 29

@iambatman

Answer 30

Huh? No just plug it in the formula and it's basic arithmetic.

\[\frac{ -3+3 }{ 2 }, \frac{ -3-4 }{ 2 } =?\]

Answer 31

0,-7/2

Answer 32

Yes, you can even see in your graph that is the middle point :)

Answer 33

See for yourself!

Answer 34

got it!! i need help with 1 more

Answer 35

number 64

Answer 36

Area of square = a^2
Area of triangle = hb/2

Answer 37

8.7/2??

Answer 38

a= 4.35km??

Answer 39

Oh wait that's not a square XD the dimensions are different, guess we'll consider it as a rectangle, Area = w*l

Answer 40

is that right??

Answer 41

No the 3.7 km is the height, and 8.7 km is the base.

\[Area = \frac{ hb }{ 2} \implies \frac{ (3.7)(8.7) }{ 2 } km^2\]

Answer 42

16???

Answer 43

Yes lol