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find volume of cone \[V=1/3\pi r^2h\] divide answer by 15
Volume of the Funnel: \[length = 8 inches\] \[radius= 3 inches\] \[Volume(Cone) = \frac{ 1 }{ 3 }\pi \times r ^ {2} \times h\] Therefore:Total amount of liquid: \[VOlume = \frac{ 1 }{ 3 } \times 3.14 * (3)^{2} * 8\] \[ = 75.36 inches ^{3}\] No. of cubic inches/minute = 15 inches ^ 3 / minute Therefore,No. of minutes required to empty the the cone/vessel: \[75.36 / 15\] = 5.024 minutes
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@CaseyCarns ah...I don't think so....currently there's a large way to go learning...
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