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Find an equation for the nth term of the sequence. -4, -16, -64, -256, ...
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The common ratio is \(\large\color{blue}{a_n \div a_{n-1} }\)
\(\large\color{blue}{a_n=a_{1} \times r^{n-1}}\) is the form
well each term is being multiplied by 4 so the sequence is geometric... and a term in a geometric series is \[a_{n} = a \times r^{n - 1}\] you know a = -4 and n = 4 so just substitute them
No, n is not 4, he is asking for any nth term in general, as I see.
an=-4*4^n-1
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4^(n-1) is not the same as 4^n-1
oh, ok thanks
yeah, just marking that, np
making a new question, can you guys hop over?
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