(08.08)

The sequence an = one third(3)n − 1 is graphed below:

coordinate plane showing the points 2, 1; 3, 3; and 4, 9

Find the average rate of change between n = 3 and n = 4.

Question

(08.08)

The sequence an = one third(3)n − 1 is graphed below:

coordinate plane showing the points 2, 1; 3, 3; and 4, 9

Find the average rate of change between n = 3 and n = 4.

anonymous · Answer

attachment

campbell_st · Answer

so you need to find the slope between the points (3, 3) and (4, 9)

campbell_st · Answer

does that make sense...

anonymous · Answer

avg rate of change
slope=y2−y1/x2−x1....solve using the points (2,9) and (4,1).
The answer would be -4 then.

anonymous · Answer

Hope it helps!!

anonymous · Answer

-4 isn't even an answer... thanks anyways

campbell_st · Answer

the points you need to use are (3, 3) and (4, 9)

the formula shown above is correct... 

but its simply 

$$\frac{a_{4} - a_{3}}{4 - 3}$$

anonymous · Answer

Is answer=6? then

campbell_st · Answer

lol... who's asking the question...

campbell_st · Answer

the solution is 

$$\frac{(9 - 3)}{(4 - 3)} = 6$$

anonymous · Answer

@campbell_st  haha yeah same 6 here too..was conforming.Previously i took other two points slope :)