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3pq^2/4p^4q^8r
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Hey To clarify.. Does the problem look like this..\[\frac{ 3pq^2 }{ 4pq ^{8r} }\]..or like this?\[\frac{ 3pq^2 }{ 4pq^8r }\]
3pq^3/4p^4q^8r
If it's the second one, then we can simply cancel out the p's and then subtract 2 from the bottom q's exponent. We can't do anything with the r since it isn't represented on the top and the 3/4 portion of the fraction is already reduced.. \[\frac{ 3 }{ 4q^6r }\]
i wrote you the right one 8 minutes ago
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