Question

3pq^3/4p^4q^8r

Answer 1

dividing powers

Answer 2

\(\bf \cfrac{3pq^3}{4p^4q^8r}\implies \cfrac{3\cancel{ p }\cancel{ qqq }}{4\cancel{ p }ppp\cancel{ qqq }qqqqqr}\implies ?\)

Answer 3

when you divide powers you can subtract them for example
\[\frac{xy^4}{x^2y^3}=\frac{y}x\]

Answer 4

or do it like jode0001

Answer 5

i know that but can you help me and explain to me how to do with more then one variable

Answer 6

just look at each set of vars individually
\[\cfrac{3~~\color{red}{p}~~\color{blue}{q^3}}{4~~\color{red}{p^4}~~\color{blue}{q^8} ~~r}\]

Answer 7

for the
p: 4-1 = 3
q: 8-3 = 5
r: 0-1 = 1
the 3/4 is a constant so we have
\[\frac3{4 ~~\color{red}{p^3}~~\color{blue}{q^5}~~r}\]

Answer 8

is that the answer

Answer 9

it right

Answer 10

and if so i do you know

Answer 11

i got it thanks