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OpenStudy (anonymous):

The table shows the movie preferences of high school and college students:

OpenStudy (anonymous):

|dw:1407435784113:dw|

OpenStudy (anonymous):

okaiii

OpenStudy (anonymous):

this is math lol

OpenStudy (anonymous):

Julie mistakenly calculated the conditional relative frequency for college students who like comedy as being 70%. What did Julie actually calculate, and what is the correct answer? A. She calculated the joint relative frequency for college/comedy. The correct value of conditional relative frequency for college students who like comedy is 28%. B. She calculated the conditional relative frequency for comedy films that are liked by college students. The correct value of conditional relative frequency for college students who like comedy is16%. C. She calculated the conditional relative frequency for comedy films that are liked by college students. The correct answer is 28%. D. She calculated the joint relative frequency for college/comedy. The correct answer is 16%.

OpenStudy (solomonzelman):

You tagged me in English to answer a MATH question? I would understand if it was the other way around, but math section is very very active, so I don't really get you.

OpenStudy (anonymous):

Please Help!

OpenStudy (anonymous):

This is the English section..

OpenStudy (anonymous):

sorry for messaging a whole bunch of pop, but I've needed help on this for a long time and no one that has sen this yet is smart enough to figure it out

OpenStudy (anonymous):

why did i just get tagged in this O_o?

OpenStudy (anonymous):

When I wrote this question, i thought i was in the math section

OpenStudy (anonymous):

i wish i could help but I'm not good at math sorry

OpenStudy (anonymous):

can someone plz help?

OpenStudy (anonymous):

are you in FLVS? is this algebra?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

you are in flvs? what lesson and what module is this

OpenStudy (anonymous):

6.05

OpenStudy (anonymous):

i would love to help you but i got this question wrong.

OpenStudy (anonymous):

i know its either b or d

OpenStudy (anonymous):

oh. mvmd. i got it

OpenStudy (anonymous):

im really not sure im doing my exams for module 7, i wish i could help. just take a guess

OpenStudy (anonymous):

ok good

OpenStudy (anonymous):

yea i think its b now that i looked at it

OpenStudy (anonymous):

@dominiquebee72 , i already did mod 7. can i help u?

OpenStudy (anonymous):

mod 7 was easy

OpenStudy (anonymous):

im doing the second exam with the word problems and im stuck on this The lengths of two sides of a triangle are shown below: Side 1: 3x2 - 4x - 1 Side 2: 4x - x2 + 5 The perimeter of the triangle is 5x3 - 2x2 + 3x - 8. Part A: What is the total length of the two sides, 1 and 2, of the triangle? (4 points) Part B: What is the length of the third side of the triangle? (4 points) Part C: Do the answers for Part A and Part B show that the polynomials are closed under addition and subtraction? Justify your answer. (2 points)

OpenStudy (anonymous):

awesome. i got 10/10 on this 1

OpenStudy (anonymous):

but my prob was a tad dif

OpenStudy (anonymous):

what was different about it?

OpenStudy (anonymous):

do u get how i got that?

OpenStudy (anonymous):

did you put the expressions in order then add them up?

OpenStudy (anonymous):

Part A (3x^2−4x−1)+(−x^2+4x+5) 2x^2+4

OpenStudy (anonymous):

yes, i forgot about the negative upfront though... my bad its good to check ur work ;)

OpenStudy (anonymous):

i just added the two sides

OpenStudy (anonymous):

and under it is that the answer? is there a negative infront of the 3 or infornt of the 2 or not

OpenStudy (anonymous):

there is no negative in the answer

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

-x^2+4x+3/x+4 when i added i got this? it seems really long compared to your answer

OpenStudy (anonymous):

lets start with the first term... how did u get -x^2 ?

OpenStudy (anonymous):

Math in english section? 0.0

OpenStudy (anonymous):

yes we established that @Kperales

OpenStudy (anonymous):

ok first i took the parenthesis away and then combined all the like terms the i rewrote 3x^-1 as 3/x then i added 5 to -1 to get 4 then i got 3/x+4-x^2+4x and then just put it in order to get what i put before

OpenStudy (anonymous):

ok hold on

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

3X^2 + -x^2 = 2x^2 -4x + 4x = 0 -1 + 5 = 4 2x^2+4

OpenStudy (anonymous):

got it?

OpenStudy (anonymous):

combine like terms first

OpenStudy (anonymous):

ok wait let me read through this

OpenStudy (anonymous):

ok so the final answer is just 2x^2+4

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

ready for part B?

OpenStudy (anonymous):

yess

OpenStudy (anonymous):

Part B \[(5x ^{3}-2x ^{2}+3x-8)-(2x ^{2}+4)\]

OpenStudy (anonymous):

is that the answer? so what did you do to get it?

OpenStudy (anonymous):

no. that is the equation

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

ok so once i solve that i should have the answer?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

5x^3-4x^2+3x-12

OpenStudy (anonymous):

is that the answer to B

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