Question

Given that f(x) = 3x + 1 and g(x) = 4x+2/3 , solve for g(f(0)).

2

6

8

9

Answer 1

If you plug 0 in for f(x) you get 1 for that equation then you plug 1 into the other equation giving you 4(1)+2/3=4+2/3=6/3=2

Answer 2

\[g(f(x)) = 4(3x+1)+\frac{ 2 }{ 3 }\]

Now find g(f(0)) by plugging 0 into the equation.

Answer 3

its answer is 14/3

Answer 4

g(x) = 4(1)+2/3=4+2/3=12+2/3=14/3

Answer 5

The best way to solve this function is:
\[g[f(x)]=4*f(x)+\frac{2}{3}\]\[f(x)=3x+1\]\[f(0)=1\]So\[g[f(0)]=g(1)\]\[g(1)=4*1+\frac{2}{3}\]\[\boxed{g(x)=\frac{14}{3}}\]

Answer 6

Well it could be divided by the whole thing but she hasn't specified with any parenthesis or anything so we can only assume.

Answer 7

its 4x+2 over 3

Answer 8

OMG that's right... I guess
\[g(x)=\frac{4x+2}{3}\]In this case the answer is \[g(1)=\frac{4*1+2}{3}\]\[\boxed{g[f(0)]=2}\]

Answer 9

They meant the f(x) part

Answer 10

There we go @D3xt3R :)

Answer 11

Ya guys can't be overcomplicating things :P

Answer 12

:D

Answer 13

haha wow joshes first comment tho