Tammy is at the dentist's office waiting on her appointment. She notices that the 6-inch-long minute hand is rotating around the clock and marking off time like degrees on a unit circle. Part 1: How many radians does the minute hand move from 1:20 to 1:55? (Hint: Find the number of degrees per minute first.) Part 2: How far does the tip of the minute hand travel during that time? Part 3: How many radians on the unit circle would the minute hand travel from 0° if it were to move 5π inches? Part 4: What is the coordinate point associated with this radian measure?
@satellite73 you have some time to help me answer these four parts? :/
@campbell_st
well 60 minutes = 2 pi radians on the clockface so 1 minute = 2pi/60 radians then 1:20 to 1:55 = 35 mins 35 minutes = 35 * 2pi/60
(b) the arc length is \[l = r \theta\] you have theta from the previous part and the minute hand is 6 inches... so r = 6
(C) you will have to use arc length again \[5\pi = 6 \times \theta\] find theta this will give the angle in radian hope it helps
by c you mean 3?
how do i find theta?
yep
and divide both sides of the equation by 6
theta=5pi/6
yes
for #2 how do i find what there asking for? l=6*theta
how to find the lenght?
well 1 minute = 2pi/60 so the 35 minutes through with the minute hand travels form and angle 35*2pi/60 or 7pi/6 thats the value of theta
so.l=6*7pi/6?
yes
can that be simplified?
well there is an obvious common factor to cancel
l=7pi?
yes
thank you for being patient... would that answer #2
its is
ok going back to question one..35*2pi/60=219.8?
no... leave the answer in terms of pi.... you are working in radian its \[\frac{35 \times 2\pi}{60}\] simplify it
can we simplify 7*2pi/12 ?
sure its 14pi/12 they are both even...
7pi/6 then?
now we have answered #1 and 2
yes
if you go back and read the posts you have the answers to 1, 2, and 3
yes i meant 3 also :) so how will we find #4
|dw:1407440174941:dw| just pick up a calculator adnd find the values of x and y
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