Please help!
Prove: sin theta-sine theta*cos^2 theta=sin^3theta

Question

anonymous · Answer

Do you know your Trig Identities?

anonymous · Answer

@phi @ganeshie8

solomonzelman · Answer

1)   factor the left side out of sine theta
2)   divide both sides by sine theta
3)   use  `sin²x+cos²x=1`

anonymous · Answer

No

solomonzelman · Answer

Let me know if you need more help.

solomonzelman · Answer

What do you mean by no ?

anonymous · Answer

How do I factor trig functions?

anonymous · Answer

I didn't mean no

anonymous · Answer

I really need help with this one

solomonzelman · Answer

sinθ- sinθcos²θ=sin³θ
                                                 factor the left side out of sinθ,
 sinθ(1- cos²θ)=sin³θ
                                                divide both sides by sinθ,
1- cos²θ=sin³θ
                                                add cos²θ to both sides


tell me what you get...

anonymous · Answer

1-coa^4 theta=sin^3 theta + coa^2 theta

anonymous · Answer

I mean cos instead of coa