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Mathematics 16 Online
OpenStudy (anonymous):

HELP The figure below shows segments AC and EF which intersect at point B. Segment AF is parallel to segment EC.

OpenStudy (anonymous):

OpenStudy (anonymous):

Which of these facts is used to prove that triangle ABF is similar to triangle CBE? Angle AFB is congruent to angle CEB because corresponding angles are congruent. Angle ABF is congruent to angle CBE because vertical angles are congruent. Line segment AF is congruent to line segment EC because parallel segments are congruent. Line segment AB is congruent to line segment FB because legs of an isosceles triangle are congruent.

OpenStudy (anonymous):

@claritamontano @SolomonZelman @Ahtisham

OpenStudy (anonymous):

i would go with c....

OpenStudy (anonymous):

i was between that one and A lol

OpenStudy (anonymous):

haha i would go with c just cause haha

OpenStudy (anonymous):

lol, one more please

OpenStudy (anonymous):

Which of these facts is used to prove that triangle ABF is similar to triangle CBE? Angle AFB is congruent to angle CEB because corresponding angles are congruent. Angle ABF is congruent to angle CBE because vertical angles are congruent. Line segment AF is congruent to line segment EC because parallel segments are congruent. Line segment AB is congruent to line segment FB because legs of an isosceles triangle are congruent.

OpenStudy (anonymous):

ya

OpenStudy (anonymous):

The figure shows three right triangles. Triangles PQS, QRS, and PRQ are similar. Theorem: If two triangles are similar, the corresponding sides are in proportion.

OpenStudy (anonymous):

OpenStudy (anonymous):

Using the given theorem, which two statements help to prove that if segment PR is x, then x2 = 97? Segment PR x segment PS = 16 Segment PR x segment SR = 36 Segment PR x segment PS = 36 Segment PR x segment SR = 81 Segment PR x segment PS = 16 Segment PR x segment SR = 81 Segment PR x segment PS = 81 Segment PR x segment SR = 16

OpenStudy (anonymous):

i dont know this one sorry..... I feel bad now, but maybe @jim_thompson5910 can help he's amazing

OpenStudy (anonymous):

okey thanks, maybe with this one lol

OpenStudy (anonymous):

Yana is using an indirect method to prove that segment DE is not parallel to segment BC in the triangle ABC shown:

OpenStudy (anonymous):

OpenStudy (anonymous):

She starts with the assumption that segment DE is parallel to segment BC. Which inequality will she use to contradict the assumption? 4:9 ≠ 6:13 4:9 ≠ 6:7 4:13 ≠ 6:9 4:5 ≠ 6:13

OpenStudy (anonymous):

I would go with a

OpenStudy (anonymous):

i got to go to sleep now sorry but @jim_thompson5910 might be able to help. bye!

jimthompson5910 (jim_thompson5910):

claritamontano is correct

OpenStudy (anonymous):

@jim_thompson5910 hey can you help me with the one that clarita tag you please

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