Question

use the quadratic formula to solve 4x^2+6x-4=0

Answer 1

x=(-b+or -sqrt(b^2-4(a)(c))/2a
a=4 b=6 c=-4
Substitute to get x

source: http://www.mathskey.com/question2answer/

Answer 2

1/2 or -2

Answer 3

\[\frac{-b\pm\sqrt{b^2-4ac}}{2a}\] with \(a=4,b=6,c=-4\)

Answer 4

course it may be easier to solve
\[2 (x+2) (2 x-1) = 0\]