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multiply (x^3/8)(x^2/5)
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you have options?
its x^5/40
a. x^1/4 b. x^5/13 c. x^3/20 d. x^31/40
I think it is D but Im not 100% sure
i got D initially but i wasn't sure either...
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I would say D
well id say that it is D
\[x ^{\frac{ 3 }{ 8 }} × x ^{\frac{ 2 }{ 5 }}?\]
yes
multiply 3/8 by 5 to get the LCM for denominator so that exponent is 15/40 then multiply 2/5 by 8 to get the lcm 16/40 then add exponents \[x ^{\frac{ 31 }{ 40 }}\]
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yep
thank you1
you're welcome
Welcome im always happy to help
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