If the discriminant is 0, how many real solutions does the quadratic equation have?
2
1
3
0
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OpenStudy (anonymous):
I'd say 1 or 2 but I'm not sure
OpenStudy (midhun.madhu1987):
If Discriminant = 0 , then the equations will have 2 real and equal roots.
If Discriminant > 0 , then the equations will have 2 real roots
If Discriminant < 0 , then the equations will have 2 imaginary roots
OpenStudy (anonymous):
So it's 2?? o.o
OpenStudy (midhun.madhu1987):
yes.. and both will be EQUAL
OpenStudy (anonymous):
lol
that is like having one
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OpenStudy (anonymous):
if \(b^2-4ac=0\) then it is a perfect square
there is one zero
it is \(-\frac{b}{2a}\)
OpenStudy (midhun.madhu1987):
But the Theory of Quadratic Equations states that it has 2 Equal roots..
OpenStudy (anonymous):
So it's not 2 i'm lost
OpenStudy (anonymous):
it is one
not two
one
OpenStudy (anonymous):
that one is often called a "repeated root" but it is one number
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OpenStudy (anonymous):
Alright, thank you.
OpenStudy (anonymous):
for example if \((x-3)^2=0\) then \(x=3\) is the only solution
OpenStudy (anonymous):
yw
OpenStudy (midhun.madhu1987):
The answer is 1 only.. but this is just an added information.. since the theory states there will be 2 roots... :)|dw:1407549294694:dw|