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solve the given equation 2 cos^2 θ − cos θ − 1 = 0
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factor
yep...factor just as you would a "regular" polynomial of second degree. It works beautifully. If you need help, we can guide you...
Factor it into parenthesis like this: (2 cos theta + )(cos theta - ). Fill in the blanks. Do you know how to do this?
I've got \[2\pi/3+2\pi k\]and \[4\pi/3+2\pi k\] is it correct?
that's for theta
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