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Mathematics 19 Online
OpenStudy (anonymous):

medals ! help with practice problems

OpenStudy (anonymous):

Find the vertices and foci of the hyperbola with equation

OpenStudy (anonymous):

@ganeshie8 same type of problem again, just want to make sure im doing them right

OpenStudy (anonymous):

the vertices would be along the y axis again

ganeshie8 (ganeshie8):

this is not ellipse

ganeshie8 (ganeshie8):

also, center is not at origin..

OpenStudy (anonymous):

oh hyperbole, i was reading another problem

ganeshie8 (ganeshie8):

use this chart :

ganeshie8 (ganeshie8):

you need to use `middle` column

OpenStudy (anonymous):

okk

ganeshie8 (ganeshie8):

Look at the given equation : center = (h, k) = ?

OpenStudy (anonymous):

4,5

ganeshie8 (ganeshie8):

careful about the signs, try again :)

OpenStudy (anonymous):

4,-5

ganeshie8 (ganeshie8):

try again

OpenStudy (anonymous):

wait should i square it?

OpenStudy (anonymous):

i used your graph and got vertices: (-1, 5), \(-7, 5) foci: (-9, 5), (1, 5)

OpenStudy (anonymous):

oh wait i was using info from the right side of the graph i think

ganeshie8 (ganeshie8):

\[\large \dfrac{(x+4)^2}{9} -\dfrac{(y-5)^2}{16} = 1\] is same as \[\large \dfrac{(x- \color{red}{-4})^2}{9} -\dfrac{(y-\color{red}{5})^2}{16} = 1\]

ganeshie8 (ganeshie8):

center = (h,k) = (-4, 5)

OpenStudy (anonymous):

its saying dfrac again

ganeshie8 (ganeshie8):

http://prntscr.com/4b3wc6

OpenStudy (anonymous):

ohhh

ganeshie8 (ganeshie8):

next, find out below : a = ? b = ?

OpenStudy (anonymous):

a= 3 b=4

ganeshie8 (ganeshie8):

Correct ! so we have : (h, k) = (-4, 5) a=3, b=4

ganeshie8 (ganeshie8):

use the given chart and find out the vertices

ganeshie8 (ganeshie8):

vertices = (h+a, k) and (h-a, k)

OpenStudy (anonymous):

(-1, 5), (-7, 5)

ganeshie8 (ganeshie8):

Correct !

OpenStudy (anonymous):

the foci(-9, 5), (1, 5)

OpenStudy (anonymous):

thanks!

ganeshie8 (ganeshie8):

np :)

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