Mathematics
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OpenStudy (anonymous):
medals ! help with practice problems
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OpenStudy (anonymous):
Find the vertices and foci of the hyperbola with equation
OpenStudy (anonymous):
@ganeshie8 same type of problem again, just want to make sure im doing them right
OpenStudy (anonymous):
the vertices would be along the y axis again
ganeshie8 (ganeshie8):
this is not ellipse
ganeshie8 (ganeshie8):
also, center is not at origin..
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OpenStudy (anonymous):
oh hyperbole, i was reading another problem
ganeshie8 (ganeshie8):
use this chart :
ganeshie8 (ganeshie8):
you need to use `middle` column
OpenStudy (anonymous):
okk
ganeshie8 (ganeshie8):
Look at the given equation :
center = (h, k) = ?
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OpenStudy (anonymous):
4,5
ganeshie8 (ganeshie8):
careful about the signs,
try again :)
OpenStudy (anonymous):
4,-5
ganeshie8 (ganeshie8):
try again
OpenStudy (anonymous):
wait should i square it?
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OpenStudy (anonymous):
i used your graph and got
vertices: (-1, 5), \(-7, 5) foci: (-9, 5), (1, 5)
OpenStudy (anonymous):
oh wait i was using info from the right side of the graph i think
ganeshie8 (ganeshie8):
\[\large \dfrac{(x+4)^2}{9} -\dfrac{(y-5)^2}{16} = 1\]
is same as
\[\large \dfrac{(x- \color{red}{-4})^2}{9} -\dfrac{(y-\color{red}{5})^2}{16} = 1\]
ganeshie8 (ganeshie8):
center = (h,k) = (-4, 5)
OpenStudy (anonymous):
its saying dfrac again
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OpenStudy (anonymous):
ohhh
ganeshie8 (ganeshie8):
next, find out below :
a = ?
b = ?
OpenStudy (anonymous):
a= 3 b=4
ganeshie8 (ganeshie8):
Correct ! so we have :
(h, k) = (-4, 5)
a=3, b=4
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ganeshie8 (ganeshie8):
use the given chart and find out the vertices
ganeshie8 (ganeshie8):
vertices = (h+a, k) and (h-a, k)
OpenStudy (anonymous):
(-1, 5), (-7, 5)
ganeshie8 (ganeshie8):
Correct !
OpenStudy (anonymous):
the foci(-9, 5), (1, 5)
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OpenStudy (anonymous):
thanks!
ganeshie8 (ganeshie8):
np :)