Can someone please help me? The position of an object at time t is given by s(t) = 3 - 4t. Find the instantaneous velocity at t = 8 by finding the derivative.
start with the equation s=3-4t can you find ds/dt ?
What is ds?
I know 3 is 0
Can I do s=3-4t s=0-4t 0=-4t t=-4
is a derivative always the coefficient of x?
@Asevilla5
the derivative of a constant number (like 3) is 0 the derviative of a number times a t (like -4t) is just the number (-4) since the position function is a straight line, then the velocity will be constant for all time so there will always be a number -4 for a line you can calculate the slope by using two different points (rise over run) but a derivative is like moving those two points so close together its like taking the slope of a single point. since the slope is being taken at a single point, there is no ∆ x like a two point equation (rise/run = ∆y/∆x) so its the slope of a point at a single instant in time
Thank you for that explanation, but i also want to know if the coefficient of x is always the derivative?
velocity is constant, it will be always -4m/sec
ohhh because it's the slope so it will always rise 4 and go left 1?
@lolabieber - you might find tis useful for understanding derivatives: http://www.mathsisfun.com/calculus/derivatives-introduction.html
okay thank you guys for all your help :) I appreciate it!
@lolabieber yes
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