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Mathematics 18 Online
OpenStudy (anonymous):

solve - sin^2 x=2 cos x-2

OpenStudy (xapproachesinfinity):

first subtract 2cosx and add 2 to both sides

OpenStudy (anonymous):

so -sin^2 x-2cosx+2=0

OpenStudy (anonymous):

then what?

OpenStudy (xapproachesinfinity):

use Pythagorean identity of trig

OpenStudy (xapproachesinfinity):

sin^2x+cos^2=1

OpenStudy (anonymous):

The cos isnt squared though so that doesn't work

OpenStudy (xapproachesinfinity):

sin is squared no? i didn't say cos

OpenStudy (anonymous):

Yes but you can't use the sin^2 x+cos^2 x=1 identity unless the cos is squared

OpenStudy (xapproachesinfinity):

I didn't mean that. what i mean is find -sin^2x in terms of cos^2x you will have all th equation as cos only

OpenStudy (anonymous):

oh so it's simply cos^2 x-1 to replace the sin^2?

OpenStudy (xapproachesinfinity):

but don't forget the negative sign that is partern with sin^2x

OpenStudy (anonymous):

i figured it out thanks!

OpenStudy (xapproachesinfinity):

ok good, you are welcome

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