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could someone please help me with this question? If 3x − 4 ≤ f(x) ≤ x^2 − 3x + 5 for x ≥ 0, find lim of f(x) as x→3
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take limit through out \[\large \lim \limits_{x\to 3} 3x − 4 ≤ \lim \limits_{x\to 3} f(x) ≤ \lim \limits_{x\to 3} x^2 − 3x + 5 \]
evaluate the limit for left and right expressions ^^
so limit = 5 ?
yes ! \[\large 5≤ \lim \limits_{x\to 3} f(x) ≤ 5\] gives you \(\large \lim \limits_{x\to 3} f(x) = 5 \)
thanks alot
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