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Determine the value of k so that the lines kx-y=-1/3 and 3y=1-6x will intersect at 1 point?
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:) solve the system of equations
Can't we go by equating coefficients only?
3y+6x-1=0 -y+kx+1/3=0
how do that this equation?
thus , add first equation to 3* second equation 3y+6x-1=0 -3y+3kx+1=0 so 3k=6
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typo -3k=6
then???
Try to find out k there by dividing by -3..
k= -2
Yep.. :)
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k= -2 this a final answer
According to Ikram, Yes this is true.. :)
Determine the value of k so that the lines kx-y=-1/3 and 3y=1-6x will not intersect?
Is this other question or the same question?
other question
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