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OpenStudy (rock_mit182):
x = 9y +13
x-13 = 9y
\[y = \-frac{ x }{ 9 } - \frac{ 13 }{ 9 }\]
OpenStudy (rock_mit182):
@iPwnBunnies @SolomonZelman @ganeshie8
OpenStudy (rock_mit182):
find:\[(h ° h ^{-1} )\]
OpenStudy (rock_mit182):
h ( x/9 - 13/ 9)
OpenStudy (rock_mit182):
(h ° h ^-1 ) = (9x +13)/(9) - (13)/(9)
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OpenStudy (rock_mit182):
(h ° h ^-1)(5) = (9(5)+13)/(9) - 13/9
OpenStudy (rock_mit182):
anyone could check my work out ?
OpenStudy (anonymous):
Where'd the x go?
OpenStudy (anonymous):
Oh... I see... carry on :)
OpenStudy (anonymous):
I'm watching you... anxiously waiting for you to slip up... and you haven't... yet ;)
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OpenStudy (rock_mit182):
(h ° h ^-1)(5 ) = 5
OpenStudy (rock_mit182):
h(x )^ -1 = x/9 - 13/9
OpenStudy (rock_mit182):
there you have, my two answers
OpenStudy (anonymous):
Very good. Now, pro-tip, if you're like me and don't like wasting precious time on things that are actually so simple, just remember the very essence of inverses...
\[\Large\left( f\circ f^{-1}\right)(x) = x\]
It won't even matter how complicated or hard the function is... if you compose a function with its inverse, it does NOTHING :D
So, next time you see anything like it, say
\[\Large \left( h\circ h^{-1}\right)(9)\]
don't hesitate, the answer is 9!!!!!!
^_^