Question

please help!

ln(x/2)+ln(x+3/5)=0
i got up to ln[(x^2+3x)/10]=0

Answer 1

that makes
\[\frac{x^2+3x}{10}=1\]

Answer 2

since \(\ln(\xi)=0\iff \xi=1\)

Answer 3

do you multiply the 10 by both sides so you have x^2+3x=10

Answer 4

yes

Answer 5

idk how to figure it out