Medal+fan for anyone who can give an answer+explanation.The equation of line XY is (y−3) = negative 2 over 3(x − 4). What is the slope of a line perpendicular to XY? −2 3 negative 2 over 3 3 over 2
put it into the proper equation of a line y=mx+b, where m is your slope. A line perpendicular to that one, would have an inverse and opposite slope, so for example if you end up 2 as your m in y=mx+b, it would be a -1/2 slope
That doesnt exactly open any options with this question. I put this up because I did that already but got stuck
i think it ends up with the line y=3x-12, perpendicular slope would be -1/3
I see where you went with it but I dont understand how it can match the answer optins if you put it like that
It got be -3/2
How did you get that?
its 3/2 not negative
I MET -2/3 because when you FOIL
teja, can you explain your answer?
yes |dw:1407713127202:dw|
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