Helppppp D: Justine performed a transformation on trapezoid ABCD to create A'B'C'D', as shown in the figure below Rotation of 270° clockwise about the origin Rotation of 90° counterclockwise about the center of the figure Rotation of 90° clockwise about the origin Rotation of 270° counterclockwise about the center of the figure ( I said C but im not sure)
@aaronq @dan815 @zmanlane
The answer is actually A
explain?
Just draw a line from the origin to the midpoint of AB. Count the number of diagonals spaces. Next rotate the line 270 degrees clockwise. Using the number of diagonals counted from the origin to the midpoint of AB and starting from the origin, count the same number of diagonals. This will be the midpoint of A'B'. All the other points have the same relationship to A'B' as AB. Or you could just draw the figure in a graphing software program like Geogebra and use the rotation tool.
A
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