Question

Find P( F | E )
E= Pointer lands on an even number
F= Pointer lands on a number less than 4

Answer 1

can you tell from the table what \(P(E)\) is ?

Answer 2

mmm not exactly, im not sure what do to with it

Answer 3

@satellite73

Answer 4

add

Answer 5

they equal 1

Answer 6

there are two even numbers
\(2\) and \(4\)

Answer 7

i didn't mean add all the numbers, they have to add to \(1\)
i meant add the probabilities for getting an even number
\[P(2)+P(4)\]

Answer 8

ahh so .4?

Answer 9

that is not the final answer, but you need that number, yes

Answer 10

\[P(F|E)=\frac{P(F\cap E)}{P(E)}\] so we need \(P(E)=.4\) as out denominator

Answer 11

so now find P(F)?

Answer 12

as * our denominator
now that we know it is \(.4\) you need \(P(E\cap F)\)

Answer 13

you need \(P(E\cap F)\) not \(P(F)\)

Answer 14

oh okay, so how do i find that?

Answer 15

in order to find it, you have to understand what \(E\cap F\) means in simple english
then i will be obvious

Answer 16

E= Pointer lands on an even number
F= Pointer lands on a number less than 4

join these two statements with the word "AND" and then restate it in plain english

Answer 17

if it is not clear let me know

Answer 18

oh so .2?

Answer 19

cause 2 would be the only even number right?

Answer 20

well \(E\cap F\) is a set, it means "you roll an even number And a number less that 4"
in english it means "your roll a two" but you are right
\[P(E\cap F)=.2\]

Answer 21

that completes finding the numbers you need for your answer

Answer 22

you get the final answer?

Answer 23

yes .5

Answer 24

yeah \[\frac{.2}{.4}=\frac{2}{4}=\frac{1}{5}=.5\]