Question

Help please!
can someone show me how to get from
[(3n - 1) / (5n+2)]
to
[((3/5)(5n+2) - (6/5) - 1) / (5n+2)] ?

Answer 1

is this your question ?

Answer 2

yes

Answer 3

help me please T.T

Answer 4

its says to use the 'juggling' method, but i dont know what is juggling method

Answer 5

first solve this :-
\[\large \bf \frac{3}{5} \times (5n+2)=\frac{15n+6}{5}\]

Answer 6

3n + (6/5)

Answer 7

then,
\[\large \bf \frac{15n+6}{5}-\frac{6}{5}-1\]
Take LCM 5,
\[\large \bf \frac{15n+6-6-5}{5}\]
we get,
\[\large \bf \frac{15n-5}{5}=\frac{15n}{5}-\frac{5}{5}=3n-1\]

After all,we get
\[\large \bf \frac{3n-1}{5n+2}=\color{red}{Answer}\]

Answer 8

understood? @HatcrewS

Answer 9

can i know what do you use to type in fraction form ?

Answer 10

uhm.. still dont quite get it.. how does the (3/5) come about in the first palce

Answer 11

place*

Answer 12

yeah,why not?

use this :-
`frac{x}{y}`=\(\large \bf \frac{x}{y}\)
{ Remember:- Type this in equation editor }

Answer 13

uhm.. sir how do you get [(3n - 1) / (5n+2)]
to
[((3/5)(5n+2) - (6/5) - 1) / (5n+2)] ?
you are solving it the other way round @@

Answer 14

in which step you stucked ? @HatcrewS

Answer 15

i dont even know how to begin

Answer 16

first of all, do you get this ?

Answer 17

\[\frac{3n-1}{5n-2} \] to \[\frac{\frac{3}{5}(5n+2) - \frac{6}{5} - 1}{5n+2}\] to \[\frac{3}{5} - \frac{11}{5(5n+2)}\]

Answer 18

sorry its \[\frac{3n-1}{5n+2}\]*

Answer 19

your last step is wrong..first solve numerator first and then go to denominator

Answer 20

@HatcrewS just concentrate on my work...

Answer 21

please read my last 3 rd comment....do you get this or not ?

Answer 22

i understand the working, but i dont know how do you get to have that equation

Answer 23

where does the \[\frac{3}{5}\] comes about ?

Answer 24

i only took this equation under red line

Answer 25

the steps that i've written are the steps given in the textbook, i just dont get it how it works

Answer 26

i solved the bracket first

Answer 27

@HatcrewS understood?

Answer 28

no. i need to understand your working. why do you bring (5n+2) to the numerator and where does the (3/5) comes from ???

Answer 29

go through your question, just find out 3/5

Answer 30

at first you only see this \[\frac{3n-1}{5n+2}\] what are the steps or mathematical method do you use to make it become like this \[\frac{\frac{3}{5}(5n+2) - \frac{6}{5} - 1}{5n+2} \]

Answer 31

no..you are saying opposite ....

Answer 32

its so hard to get this 2 nd equation from 1 st equation

Answer 33

exactly... thats what ive been talking about... its from 1st equation to 2nd equation =.="

Answer 34

no,its not easy....

Answer 35

its the other way round sir xD

Answer 36

sir ??? who is sir here ?

Answer 37

i am not a sir

Answer 38

just tell me mayank

Answer 39

sorry.. okay

Answer 40

k

Answer 41

can you show your work(textbook solution)? from this , i can tell you

Answer 42

ok hold on

Answer 43

tbh the textbook also nvr say much

Answer 44

what?

Answer 45

just click image of your solution and then attach it

Answer 46

there