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Trigonometry
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(sin(5x))^4=(3/8)-1/2cos(10x)+1/8cos(20x)
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I used half angle identity. \[\sin(a/2)=\pm \sqrt(\frac{ 1-\cos(a) }{ 2 }\]
so my question is how would you solve (sin(5x))^4 to get that answer
could take the sqrt(1-cos(a)/2)^4 and A would be 10x
because were taking it to an even power (4) the +/- would just become + and the -cos(a) would become +cos(a)
not solving for x just need help proving it.
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