Another functions questions?
Let f(x) = 2x + 2. Solve f-1(x) when x = 4. 1 3 4 10
2x + 2 2 (4) + 2 8 + 2 10 But I don't get what the f-1(x) is so I don't know if im right or not?
@Mokeira
it simply means inverse
so I'm right? inverse = opposite doesn't it?
or its 1 actually?
This is how you do it \[2x+2=\frac{ 1 }{ 2 }x+2\] you inverse the 2 that has x
then substitute
hope you get what I am trying to say
@CrazyTurtle483
sorry i had to go get dogs in
yea i kinda do it's kind of confusing
when i do it on paper i get 1
basically it means inverse the value that has x...in this case, 2x, we inverse 2
you should get 4
\[\frac{ 1 }{ 2 }x+2=(\frac{ 1 }{ 2 }\times 4)+2\] \[=2+2\] =4
Let f(x) = 2x + 2. Solve f-1(x) when x = 4. f(x) returns a number. call it y. \(f^{-1}(y)\) takes the out of f(x), and returns the x
in other words \[ f^{-1}(4) \] means the output of f(x) = 4 and we want to find x. f(x) = 2x + 2 4 = 2x+2 solve for x add -2 to both sides: 4-2 = 2x +2-2 2= 2x divide both sides by 2 1= x 1 is the answer
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