Question

Please help! Will fan and medal!
a. How many real solutions does the equation
0.2x^5 -2x^3 +1.8x +k =0 have when k = 0?

b. How many real solutions does it have when k=1?

c. Is there a value of k for which the equation has just one real solution?

d. Is there a value of k for which the equation has no real solution?

Answer 1

Here's the equation again in case the one I typed out in the question is difficult to read:
\[0.2x^5-2x^3+1.8x+k=0\]

Answer 2

Do you know Descartes' Rule of Signs?

Answer 3

I do not.

Answer 4

0.2x^5 -2x^3 +1.8x +k =0

thus
0.2x^5 -2x^3 +1.8x =0
x(0.2x^4-2x^2+1.8 )=0

Answer 5

So what do I do with the equation you've given me to answer the questions above?

Answer 6

@ikram002p