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Biology 14 Online
OpenStudy (redohawk):

Hemophilia is a blood clotting disorder that is a sex-linked trait carried on the X chromosome. If a woman with hemophilia and a man without the disorder have two sons and two daughters, how many of their children would have hemophilia? None One Two Four

OpenStudy (redohawk):

@UmarsBack @tHe_FiZiCx99 @camerondoherty @king_kong_killer

OpenStudy (anonymous):

i think its d but don't rely on my answer because i'm not to great with science

OpenStudy (agreene):

since it is x linked and the mother is positive, both sons will have it because they will get their X from the mother (who has it) but they will get a Y from the father. Neither daughter will have it because they will get the X from the mother and X from the father, but since it is recessive they will just become carriers of it.

OpenStudy (ookawaiioo):

All of her sons would be infected........X*Y The daughters would be heterozygous for it. X*X X* = infected gene X = normal gene

OpenStudy (ookawaiioo):

Its hemophilia is sex-linked recessive, then none of the daughters are infected. I think its this is the case.

OpenStudy (redohawk):

@king_kong_killer I don't know which answer is right, and i don't know which answer is wrong coz i skipped it and said i will do it later, but then i submitted it without answering. Anyway, I am gonna give you a medal for being here first, and coz your nice ;)

OpenStudy (anonymous):

haha yay :))))) @RedoHawk

OpenStudy (kainui):

@Somy @KL-RC

OpenStudy (ookawaiioo):

I gave you the answer....... *Facepalm*

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