Question

Really need help:( @Broskishelleh @phi @jdoe0001 @xapproachesinfinity

Answer 1

Belinda wants to invest $1000. The table below shows the value of her investment under two different options for two different years:

Number of years 1 2 3
Option 1 (amount in dollars) 1300 1600 1900
Option 2 (amount in dollars) 1120 1254.40 1404.93


Part A: What type of function, linear or exponential, can be used to describe the value of the investment after a fixed number of years using option 1 and option 2? Explain your answer.
Part B: Write one function for each option to describe the value of the investment f(n), in dollars, after n years.

Part C: Belinda wants to invest in an option that would help to increase her investment value by the greatest amount in 20 years. Which option should Belinda choose? Explain your answer, and show the investment value after 20 years for each option.

Answer 2

so far i got Option 1 is linear and option 2 is exponentiation. Option 2 gives more money than option 1.

Answer 3

Part B: Write one function for each option
can you do that for the linear function?

Answer 4

that's what im struggling with

Answer 5

you have
1 2 3
1300 1600 1900

what is the difference between the terms? 300
if you multiply the t-1 times 300 you get the amount to add to 1300
for year t

Answer 6

t-1*300

Answer 7

put t-1 in parens

add 1300

Answer 8

(t-1)+30 its supposed to look like this?

Answer 9

1300 i meqn

Answer 10

the idea is you want a rule that tells you the amount you have after t years

in other words, when t is 1, we want to get 1300
when t is 2 we want to get 1600

(t-1)*300 + 1300

Answer 11

100(3t+10)

Answer 12

when i combine like you said i get 100(3t+10)

Answer 13

confused on simplifying 300t+1000

Answer 14

How (and why) did you get 100(3t+10) ?

the rule is
(t-1)*300 + 1300

you could write that as 300t -300+1300 = 300t +1000
but I would not bother.

in other words

(t-1)*300 + 1300
and
300t +1000
will give the same number.

what number do you get for t=2 ?

Answer 15

use either (t-1)*300 + 1300
or 300t +1000

Answer 16

how does the first part equal 300t again ? i got 1600.

Answer 17

can you explain part c

Answer 18

I just wanted to show that the rule
300t + 1000
gives the numbers in your table
t 1 2 3
amount 1300 1600 1900

when t is 2, you should get 1600.
when t is 3, you should get 1900
if you get those numbers, then the rule is working

Answer 19

to figure out the rule, notice we have an arithmetic sequence
and you probably learned how to find the nth term using
An= start + (n-1)*d
where d is the difference, and n is which term

in this case, we used t instead of n.
the start is 1300
d is 300
n is renamed t
we get the rule
A_t = 1300 + (t-1)*300

Answer 20

for the other sequence, it is a geometric sequence.

Did you learn how to find the nth term of a geometric sequence ?

Answer 21

i get the first part. what about c and no i havent learned that. Part C: Belinda wants to invest in an option that would help to increase her investment value by the greatest amount in 20 years. Which option should Belinda choose? Explain your answer, and show the investment value after 20 years for each option. (4 points)