Find the solution to the following equation.

Select one:
a. –3
b. -1/3
c.1/3
d. Undefined

Question

Find the solution to the following equation.


Select one:
a. –3
b. -1/3
c.1/3
d. Undefined

anonymous · Answer

attachment

solomonzelman · Answer

following equation ?

solomonzelman · Answer

It is definitely not D, because there is no such a thing as an 'undefined solution' it is called no solution :)

solomonzelman · Answer

$\normalsize\color{black}{\sqrt[3]{x^3-3x}+1=x}$

anonymous · Answer

is it 1/3?

anonymous · Answer

@SolomonZelman

solomonzelman · Answer

$\normalsize\color{black}{ \sqrt[3]{x^3-3x^2}-1=x}$    add 1 to both sides,

$\normalsize\color{black}{ \sqrt[3]{x^3-3x^2}=x+1}$     cube both sides,

$\normalsize\color{black}{ x^3-3x^2=(x+1)^3}$       

$\normalsize\color{black}{ x^3-3x^2=(x+1)(x^2+2x+1)}$

$\normalsize\color{black}{ x^3-3x^2=x^3+3x^2+3x+1}$

$\normalsize\color{black}{ -3x^2=3x^2+3x+1}$

$\normalsize\color{black}{ -6x^2-3x-1=0}$

solomonzelman · Answer

Multiply everything times -1,       $\normalsize\color{black}{ 6x^2+3x+1=0}$
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