Question

What is the solution to 8x-2=x^2?

Answer 1

Why not write it in standard Quadratic Equation Form and solve with your usual methods?

Answer 2

I made the equation equal 0 and Im factoring.

Answer 3

It's not likely that it will factor. Quadratic Formula?

Answer 4

The equation when equaling 0 is \[-x^2+8x-2=0\]

Answer 5

.you could use completeing the square to factor i think.

Answer 6

Like square both sides before making the equation equal 0?

Answer 7

Don't make your life difficult. Use \(x^{2} - 8x + 2 = 0\). This is standard Form.

Completing the Square is the same as the quadratic formula. Unique answers don't care how you find the,.

Answer 8

\[-x^2+8x-2=0\]
\[-1(-x^2+8x-2)=0(-1)\]
\[x^2-8x+2=0\]
\[x^2-8x=-2\]
\[x^2-8x+16=-2+16=14\]
\[(x-4)(x-4)=14\]
\[x-4= \pm \sqrt{14}\]

Answer 9

quadratic formula is easier, I just dont think you should get to dependent on the quadratic formula.

Answer 10

Quadratic Formula and Completing the Square are the same thing in an algebra problem. In the calculus, you will be very glad that you are good at Completing the Square. You'll need that.

Answer 11

Quadratic Formula

\[ax^2+bx+c\]

\[\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]

Answer 12

I was with you until the 5th step. How did you get the 16=-2+16=14?

Answer 13

ok so this is completeing the square method, and the 16 is we take half of 8 = 4 then square it to get 16.

8 is the "b" term

Answer 14

er b coefficient

Answer 15

half of b squared , then add that number to both sides.

Answer 16

thats just how you get a perfect square so it factors out.

Answer 17

Think really hard on this concept: \((a+b)^{2} = a^{2} + 2ab + b^{2}\)

Answer 18

if you just need to get the problem done fast, just plug it in to the quadratic formula.

Answer 19

Ok, thank you.

Answer 20

i think i got around x=7.74 and x=0.25 something around there.