Question

Determine f(2), f(t-4).
a.) f(x) = x^2 + 9
b.) f(x) = x^2 + 3x + 2

Answer 1

plz explain

Answer 2

\[f(\color{red}{x}) =\color{red}{x^2}+9\\f(\color{red}{2}) =\color{red}{2^2}+9=13\]
can you do the rest?

Answer 3

that yes but the t-4 part no

Answer 4

plug in t-4 for x

Answer 5

see what you get

Answer 6

\(\huge \color{green}{f(\color{red}{t-4})=[~~~~~~]^2+9}\)
in the barackets put t-4 instead of x
\(\huge \color{green}{f(\color{red}{t-4})=[\color{red}{t-4}]^2+9}\)

Answer 7

can you do it now?

Answer 8

instead of x you put t-4, the same if it is 2 or any other
number or expression

Answer 9

but wat is (t-4)^2

Answer 10

im not suppose to use a calculator

Answer 11

you don't know how to expand that
\(\huge \color{brown}{(t-4)^2=(t-4)(t-4)}\)
Foil and you have
\(\huge \color{brown}{(t-4)(t-4)=t^2-4t-4t-4(-4)\\~~~~~~~~~~~~~~~~~~~~~=t^2-8t+16}\)

Answer 12

Do you know how to do this?

Answer 13

\(\huge \color{brown}{(a+b)^2=a^2+2ab+b^2}\)
this is called binomial expansion you should be able to this by now
since you are taking that course!

Answer 14

ok i got ti now thank you

Answer 15

\(\Huge \frak\color{blueviolet}{\bigstar~you~are ~welcome\bigstar}\)