Question

FAN AND MEDAL
Fe2+ + Cl2 --> Fe3+ + Cl–
a. Write the oxidation and reduction half-reactions. Make sure each half-reaction is balanced for number of atoms and charge.
b. Equalize charges for the two half-reactions.
c. Add the equations and simplify to get a balanced equation.

Answer 1

if someone could please solve this, it'd be great

Answer 2

@Abhisar

Answer 3

Fe2 + Cl2 -> Fe3+ + Cl-

clearly Cl is gaining an electrons (hence the negative charge)
and Iron is losing electrons (Hence the positive charge)

when something is bonded to itself it has an oxidation state of zero
When it has a negative charge it has more electrons than protons
When it has a positive charge it has less electrons than protons

Answer 4

sorry could you just please type the answer. this assignment is due in like 10 min. i'll re-study this using a different textbook later

Answer 5

He gave a good explanation!

Answer 6

2e- + Cl2(g) --> 2Cl-(aq) reduction

Answer 7

good

Answer 8

i have no idea about the oxidation though..

Answer 9

Balanced Equation = 3Fe2 + Cl2 —> 2 Fe3 + 2 Cl

Answer 10

It is just with the Fe

Answer 11

remember oxidation is loss of electrons which means it will be in the product

Answer 12

the electrons that is

Answer 13

so it'd be like (Fe)-->

Answer 14

2Fe2+ ----> 2Fe3+ + 2e-

Answer 15

Yes

Answer 16

is that righ...?

Answer 17

that is right good job

Answer 18

you can do this stuff you dont need me to give you the answer

Answer 19

thank you! very helpful. i really don't understand the whole equalizer eh charge thing for the two half-reactions.

Answer 20

so how can i equalize it...

Answer 21

They are equalized there are 2 electrons on the left side and 2 electrons on the right side when you add both half reactions together

Answer 22

ah okay. i got it! finally understand :) thanks so much

Answer 23

so electrons cancel out

Answer 24

you are left with a balanced equation

Answer 25

Your original balanced equation makes no sense

Answer 26

3Fe2 + Cl2 —> 2 Fe3 + 2 Cl

You have 6 Fe on the left and 2 Fe on the right

Answer 27

just pointing this out though

Answer 28

sorry last thing. is this correct: Half-Reactions: Zn(s) → Zn²⁺(aq) + 2e⁻, Cu²⁺(aq) + 2e⁻ → Cu(s)
Zn²⁺(aq) + 2e⁻ → Zn(s) E⁰red = -0.762 VZn(s) → Zn²⁺(aq) + 2e⁻ E⁰ox = +0.762 V
Cu²⁺(aq) + 2e⁻ → Cu(s) E⁰red = +0.339 VZn(s) → Zn²⁺(aq) + 2e⁻ E⁰ox = +0.762 VCu²⁺(aq) + Zn(s) → Cu(s) + Zn²⁺(aq) E⁰cell = + 1.101 V

Answer 29

for the cell potential

Answer 30

and also, is the oxidation state of Cl2 supposed to be 0?

Answer 31

Yes

Answer 32

my teacher said -1... but I'm sure its 0

Answer 33

When an atom is bonded to itself it counts as 0 oxidation state
when an atom is bonded to a more electronegative atom it has a +1 oxidation state
when an atom is bonded to a less electronegative atom it has a -1 oxidation state

Answer 34

your teacher is wrong

Answer 35

Cl2 has an oxidation state of zero because they have an equal pull on eachothers electrons

Answer 36

As for your last question if you followed the formula I posted in your previous question it is correct anyways I'm going to sleep is the number on the end of your name a zip code or am I crazy, just curious I dont really care if you answer

Answer 37

good luck on your assignment I hope I was helpful

Answer 38

haha yea the number is my zip code but i moved for high school so it doesn't matter. thanks! your answers were really helpful and thanks for being so patient. I am awful at chemistry.. doesn't make sense to me. thanks a lot :)