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OpenStudy (dannyrod2000):
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OpenStudy (dannyrod2000):
@triciaal
OpenStudy (dannyrod2000):
i had trouble with this question
OpenStudy (triciaal):
use the same principle
what are the factors of 72 x^3 and 50 x^2
OpenStudy (dannyrod2000):
9 and 8. 10 and 5
OpenStudy (triciaal):
yes those are factors but we are interested in
prime factors and perfect square factors
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OpenStudy (triciaal):
for 72 use 2 *36 to give 6 rt 2 why?
break 9 * 8 down to 3 * 3 * 2 *2*2
when you take the root = 3*2 *rt 2 = 6 rt 2
OpenStudy (triciaal):
factors of 50 you have 10 and 5 but 10 can be broken down to 2 * 5 (we want prime factors)
rt 50 x^2 = rt (2 * 5 * 5 * x * x)
=5 x rt 2
OpenStudy (dannyrod2000):
so we keep everything the same and it is A?
OpenStudy (triciaal):
original 72 x^3 / 50 x ^2
express with the factors then simplify
OpenStudy (aum):
\[ \Large
\frac { \sqrt{72x^3} }{\sqrt{50x^2}} = \sqrt{\frac{72x^3}{50x^2}} = \sqrt{\frac{36x}{25}}
= \frac 65\sqrt{x}
\]
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OpenStudy (triciaal):
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