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Mathematics 21 Online
OpenStudy (dannyrod2000):

http://prntscr.com/4cbg5u

OpenStudy (dannyrod2000):

@triciaal

OpenStudy (dannyrod2000):

i had trouble with this question

OpenStudy (triciaal):

use the same principle what are the factors of 72 x^3 and 50 x^2

OpenStudy (dannyrod2000):

9 and 8. 10 and 5

OpenStudy (triciaal):

yes those are factors but we are interested in prime factors and perfect square factors

OpenStudy (triciaal):

for 72 use 2 *36 to give 6 rt 2 why? break 9 * 8 down to 3 * 3 * 2 *2*2 when you take the root = 3*2 *rt 2 = 6 rt 2

OpenStudy (triciaal):

factors of 50 you have 10 and 5 but 10 can be broken down to 2 * 5 (we want prime factors) rt 50 x^2 = rt (2 * 5 * 5 * x * x) =5 x rt 2

OpenStudy (dannyrod2000):

so we keep everything the same and it is A?

OpenStudy (triciaal):

original 72 x^3 / 50 x ^2 express with the factors then simplify

OpenStudy (aum):

\[ \Large \frac { \sqrt{72x^3} }{\sqrt{50x^2}} = \sqrt{\frac{72x^3}{50x^2}} = \sqrt{\frac{36x}{25}} = \frac 65\sqrt{x} \]

OpenStudy (triciaal):

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