Question

hey so i dont really understand f of x. i mean i kinda do but then i get a problem like this
Let f(x) = x + 8 and g(x) = x2 - 6x - 7. Find f(g(2)).

and im so confused! please help

Answer 1

do you have multiple choice answers? if so please show them :)

Answer 2

to get g(2) you just need to plug in x=2
in g(x)

what would you get as g(2) ? try...

Answer 3

im in algebra 2 and im good at math but this is the one thing i never understood.

Answer 4

plus im a little rusty

Answer 5

((2)2-6(2)-7)+8

Answer 6

example if \(f(x) = x^2+ 4x \\ f(\heartsuit) = \heartsuit^2 +4 \heartsuit \)

Answer 7

\(g(x) = x^2-6x-7 \\ g(2) = ... ?\)

Answer 8

\(\normalsize\color{blue}{ f(x) = x + 8}\)
\(\normalsize\color{blue}{g(x) = x^2 - 6x - 7}\)

\(\normalsize\color{blue}{f(g(x)) = (x^2 - 6x - 7) + 8}\)
\(\normalsize\color{blue}{f(g(x)) = x^2 - 6x - 7 + 8}\)
\(\normalsize\color{blue}{f(g(x)) = x^2 - 6x + 1}\)

\(\normalsize\color{blue}{f(g(2)) = (2)^2 - 6(2) + 1}\)
\(\normalsize\color{blue}{f(g(2)) =4 - 12+ 1}\)
\(\normalsize\color{blue}{f(g(2)) =??}\) you tell me

Answer 9

Plug in 2 in g(x) and then plug g(x) in the x if f(x) ..

Answer 10

y=f(x) is y as a function of x
f(x) = x + 8 and g(x) = x2 - 6x - 7. then f(g(2))
f(g(x)).= x^2 - 6x - 7. + 8
put g(x) in place of x
f(g(2))=2^2 - 6*2 - 7. + 8
4+8-7-12
=-7

Answer 11

Of*

Answer 12

I would normally imagine something like g(f(x)) g of f, not f of g (in this case) ....

Answer 13

i have processing problems so it may take me a second

Answer 14

sure

Answer 15

@SolomonZelman i got -7. i understand it now!!!! thank you and everyone else for there help

Answer 16

-7 is right! ... Anytime!