Question

http://prntscr.com/4cipxt

Answer 1

The domain of \(\sqrt{f(x)}\) is all values of \(x\) such that \(f(x)\ge0\).

If \(f(x)=x-1\), for what values of \(x\) is \(x-1\ge0\)?

Answer 2

so the answer would be \[x-1\ge0?\]

Answer 3

@agreene

Answer 4

@SolomonZelman

Answer 5

Yes, but how else can you write the inequality?