Find the equation of the line that passes through (0,20) and (4, 4). (You have already calculated the slope in question 13) y = -4x + 20 y = -4x+ 4 y = -0.25x + 20 y = 0.25x + 4
@Nnesha
What was the slope that you calculated in question 13?
-4
use the point slope formula \[y-y_1=m(x-x_1)\] plug in one of the given points in (x1,y1) and plug the slope which represents m in this formula
0_o
so use this formula y=mx + b where m is a slope and b is y -intercept put the one of your favourite order pair in to the equation
that looks like inter galactic alien language to me :D
so y = -4x + 20
no?
you know the m=-4 so you can see that c and d are not have -4 as a slope sooooo that are wrong and now we have a and b
or use y=mx+b the slope intercept form and use one of the given points, let's say (0,20) and plug them with the slope as well and substitute y=(-4)·x+b y=(-4)·(0)+b (20)=(-4)·(0)+b
right you got the right answer
you're looking for the y-intercept or b, in this equation (20)=(-4)·(0)+b
thank you guys sooooooooooooo much for your patience and help :D
i seriously suck
you most welcome :) :)
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