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Kelly tells you that when variables are in the denominator, the equation becomes unsolvable. "There is a value for x that makes the denominator zero, and you can't divide by zero," Kelly explains. Using complete sentences, demonstrate to Kelly how the equation is still solvable. @IMStuck
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Yes your back quick
As long as the integer you put in for x in the denominator doesn't make the denominator equal zero, it can be done.
Alright take your time
Zeros in the denominator are illegal, math-wise, because the function is undefined there.
Can you demonstrate as was well please
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Sure, like this:
Thanks
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