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Mathematics 24 Online
OpenStudy (anonymous):

i'll attach the graph

OpenStudy (anonymous):

OpenStudy (anonymous):

@abb0t

OpenStudy (abb0t):

The domain is ALL numbers except that one that makes the denominator zero or the function undefined. So, looking at only the denominator, \(\sf \sqrt{x+2}=0\), now solve for "x".

OpenStudy (abb0t):

The range is not the "x" but rather, the "y" Variable.

OpenStudy (anonymous):

B?

OpenStudy (abb0t):

Close, but not quite.

OpenStudy (anonymous):

A or C then

OpenStudy (abb0t):

It is actually \(\sf \mathbb{R} > 0\)

OpenStudy (abb0t):

all numbers that are positive, greater than zero.

OpenStudy (anonymous):

doesn't it have to be c

OpenStudy (abb0t):

Yes ma'am.

OpenStudy (anonymous):

thanks!

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