Question

Travis is riding the Ferris wheel at the amusement park. His height can be modeled by the equation H(t) = 22 cos pi over 13t + 28, where H represents the height of the person above the ground in feet at t seconds.

Answer 1

1. Part 1: How far above the ground is Travis before the ride begins?
Part 2: How long does the Ferris wheel take to make one complete revolution?
Part 3: Assuming Travis begins the ride at the top, how far from the ground is the edge of the Ferris wheel, when Travis' height above the ground reaches a minimum?

Answer 2

@aryandecoolest can you help?

Answer 3

oh!ok!! before ride begins. t=0 so
\[22 \cos (\pi/13)*0 + 28\] ------>22+28=50

Answer 4

2. Time period=\[2\pi/B\]
\[B=\pi/18\] so time period for one revolution is
\[2π/(π/13)=26 \sec\]

Answer 5

there above.... B=pi/13, my bad.

Answer 6

I notice that but I knew what you meant, but where does the 2pi come from, from 2π/(π/13)=26sec

Answer 7

That's a relation.. The equation is in from of
\[y=Acos(Bx-C)+D\]
\[amplitude=22\]
\[ B=π/13\]

Answer 8

Oh ok, I see

Answer 9

in part 3, do I combine part 1 and part 2 answers?

Answer 10

you know when the cos function has minimum value @morningskye123

Answer 11

is that a question? if it is im not to sure, trig- is weird and difficult. Is the mini going to be in (bx - c)?

Answer 12

it will be minimum at t=1/2----> t=26/2
=13 sec, so from above equation we can also co relate value for vertical shift=28. ACtually vertical shift is the measure of how far the graph has shifted vertically, either up or down, from its initial position...
so anyways, at t=13
\[H(13)=22\cos(π/13*13)+vertical shift \]
\[H(13)=22*(-1)+ 28=6\]
so it gives 6ft.

Answer 13

Omg, thank you and that makes a lot of sense. So, thank you again

Answer 14

lol!! np) anytime. :)

Answer 15

Here's a metal :D