how do you write an equation in slope intercept form for the line that satisfies each set of conditions.

Find a line that passes through (3,1) perpendicular to the graph of y=-3x+2

did i do it right i got y=1/2x-.5

Question

how do you write an equation in slope intercept form for the line that satisfies each set of conditions.

Find a line that passes through (3,1) perpendicular to the graph of y=-3x+2

did i do it right i got y=1/2x-.5

mokeira · Answer

@soccerplayer46

anonymous · Answer

then whats b

anonymous · Answer

@Mokeira

mokeira · Answer

b what?

anonymous · Answer

for the equation to be in slope intercept form it has to be y=mx +b

anonymous · Answer

wouldnt it be that you have to change the slope of $$y=-3x+2$$ into a slope of 1/3 and then just plug in (3,1) into the equation $$y=1/3x+b$$ it gives you 1=1/3(3)+b so 1=3+b and b=-2 so the final answer is $$y=1/3x-2$$

anonymous · Answer

@soccerplayer46 does that work for you or do you need a better explanation

mokeira · Answer

@tiguebaxter  is my answer ok though?

mokeira · Answer

i dont get how you have changed the slope

anonymous · Answer

the problem with your answer is you didnt account for the perpendicular aspect so you have to find the opposite reciprocal of the original slope given by the first line $$y=-3x+2$$
the slope of that line is -3 so the opposite reciprocal is 1/3

mokeira · Answer

ooo...yeah, i get your point. I have seen my mistake

anonymous · Answer

alright good im glad i could help @Mokeira  and @soccerplayer46