PLS help i really dont get this, lesson didnt help. Which function has the greatest y-intercept?
So, y intercepts happen when \(x=0\) this is because if you look, when x is 0 the graph will be somewhere on the y axis. for these examples; \[f(0)=-3(0)-5\\h(0)=2\cos(2(0)-\pi)+4\] for g(0) we can look at the graph and see it intercepts at 3 So, evaluate the above, and see which one gives the highest value
y= mx + b Where b, the number by itself, is the y-intercept, so the largest number on the end is the largest y-intercept
what @DarronW said is true of linear equations like \(f(x)\) in this problem, but not necessarily to everything
My example was a linear formula, feel free to give an example where the y-intercept is ever different from a lone number in function notation.
okay, so wait solve both the f(0) and h(o) for highest value?
right, and i said g(0) wrong, it is actually -3 not 3
@DarronW \(h(x)\) in this example would be something where the trailing addition is not the intercept
When i solved with the x=0 i got f(0)=-5 and h(0)= -5.996 Did I follow that right?
you did h(0) incorrectly; \[h(0)=2\cos(-\pi)+4=2(-1)+4\\h(0)=2\]
okay so from there would the answer be f(x)?
No, look again: \[f(0)=-5\\g(0)=-3\\h(0)=2\]
oh! So h(0) would be right because its greater right?
right!
omg! thnx
no problem :)
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