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Find the derivative of f(x) = 12x^2 + 8x at x = 9 256 -243 288 224
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use the chain rule \[\Large \frac{ d }{ dx }(x^n)=n*x^{n-1}\]
can u do it now?
Never learned a chain rule
ok just use the above formula \[u ~~have ~~~f(x)=12x^2+8x\] now using the formula \[f'(x)=12[2.x^{2-1}]+8=12.[2x]=8=24x+8\] now just put x=9 \[f'(x=9)=24*9+8=224\]
Alright, I got it now. Thanks, man!
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yw bud !!
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